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akshay

I am sure there is a better way than cloning the vector over and over again 🙈

An attempt at implementing traverse to convert a Vec<Result<A,B>> to a Result<Vec<A>,B> Code: // Me: Mom, can we have travese. // Mom: We got traverse at home. // Travese at home: fn traverse_results<A, B>(results: Vec<Result<A, B>>) -> Result<Vec<A>, B> where Vec<A>: Clone, { results.into_iter().fold(Ok(Vec::new()), |acc, res| { acc.and_then(|vec| { res.and_then(|r| { let mut vectemp = vec.clone(); vectemp.push(r); Ok(vectemp) }) }) }) }
#rust
Jan :rust: :ferris:

@akshay You will be surprised how easy this actually is in Rust (still needs to allocate a new vec, though):

results.into_iter().collect();

Playground (with some explanation):
play.rust-lang.org/?version=st

I don't know Haskell, but maybe this is like `traverse` in Haskell (I've seen you've talked about it in your prev toots)!?

play.rust-lang.orgRust PlaygroundA browser interface to the Rust compiler to experiment with the language
Dec 02, 2023, 01:18 PM·Quiet public
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